9n-4=3n^2-0.75

Solution for 9n-4=3n^2-0.75 equation:

9n-4=3n^2-0.75

We move all terms to the left:

9n-4-(3n^2-0.75)=0

We get rid of parentheses

-3n^2+9n+0.75-4=0

We add all the numbers together, and all the variables

-3n^2+9n-3.25=0

a = -3; b = 9; c = -3.25;
Δ = b2-4ac
Δ = 92-4·(-3)·(-3.25)
Δ = 42
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{42}}{2*-3}=\frac{-9-\sqrt{42}}{-6}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{42}}{2*-3}=\frac{-9+\sqrt{42}}{-6}
$